Fix for 1003315: dry-run + alter-fk-method = auto always fail.

This commit is contained in:
Brian Fraser fraserb@gmail.com
2012-05-30 14:27:07 -03:00
parent 56d3d9a3b5
commit 8e04e3df60
4 changed files with 91 additions and 1 deletions

View File

@@ -29,7 +29,7 @@ elsif ( !$slave_dbh ) {
plan skip_all => 'Cannot connect to sandbox slave1';
}
else {
plan tests => 3;
plan tests => 6;
}
# The sandbox servers run with lock_wait_timeout=3 and it's not dynamic
@@ -83,6 +83,34 @@ unlike $output,
qr/\QThe original table `test1002448`.`table_name` does not have a PRIMARY KEY or a unique index which is required for the DELETE trigger/,
"Bug 1002448: mistakenly uses indexes instead of keys";
# ############################################################################
# https://bugs.launchpad.net/percona-toolkit/+bug/1003315
# ############################################################################
$sb->load_file('master', "$sample/bug-1003315.sql");
# Have to use full_output here, because the error message may happen during
# cleanup, and so won't be caught by output().
($output, $exit_status) = full_output(
sub { pt_online_schema_change::main(@args,
"$master_dsn,D=test1003315,t=A",
"--alter", "ENGINE=InnoDB",
"--alter-foreign-keys-method", "auto",
"--dry-run",
qw(--chunk-size 2 --dry-run --print))
},
);
is $exit_status, 0, "Bug 1003315: Correct exit value for a dry run";
unlike $output,
qr/\QError updating foreign key constraints: Invalid --alter-foreign-keys-method:/,
"Bug 1003315: No error when combining --alter-foreign-keys-method auto and --dry-run";
like $output,
qr/\QNot updating foreign key constraints because this is a dry run./,
"Bug 1003315: But now we do get an explanation from --dry-run";
# #############################################################################
# Done.
# #############################################################################

View File

@@ -0,0 +1,23 @@
drop database if exists test1003315;
create database test1003315;
use test1003315;
DROP TABLE IF EXISTS `B`;
DROP TABLE IF EXISTS `A`;
CREATE TABLE `A` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`foo` varchar(30) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB;
DROP TABLE IF EXISTS `B`;
CREATE TABLE `B` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`a` int(11) NOT NULL,
KEY `9dde1f34` (`a`),
PRIMARY KEY (`id`),
CONSTRAINT `6970ddb42bec57fc` FOREIGN KEY (`a`) REFERENCES `A` (`id`)
) ENGINE=InnoDB;
INSERT INTO `A` VALUES (1,'bar'), (2,'bar2'), (3,'bar3');
INSERT INTO `B` VALUES (1, 1), (2, 2), (3, 1);